GRE考试数学题如何攻破?相信这是各位需要参加考试的考生都想找到的一种方法,在此小编奉上精心整理的GRE考试数学题做法全解,以供各位考生参阅。 + plus
* S& @, U+ k+ w* }+ o5 l e4 o - minus
$ j+ G4 ^$ a' k, q * multiplied by ;times$ q/ B9 F+ d3 s. e+ S$ N# p/ Z+ _
÷ divided by
, B+ u, x9 {. ]8 F' N = equals2 x2 A# S- ]8 w& e) a) H
≈ approximately equals
. n! u& [2 [% y, E6 p/ J ≠ not equal to
# Y7 y; `9 r" }5 R( h+ C' o < less than) \7 }- B( \" r" J! J# v# I
> greater than: _$ M8 V1 V3 L
≤ equal to or less than& Z- l. N; M$ J3 ]. |. L3 h* a" p
≥ equal to or greater than
! O9 p8 }. V+ m9 d8 d) \2 ^: t ()7 P/ C& q( u, t$ t8 E. |0 G6 D
round brackets ;parentheses0 ^' Y3 C: B( g! w8 B
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& R9 k) l- O( g square brackets3 }- \; u5 M5 }7 k
{ }$ {8 J: f1 ~+ r. h8 H! m* C, p) h/ K
braces) F/ V# @# z8 n- _; T4 A
∈ is a member of the set
4 _+ T( S$ h- x1 f/ \* r# e is a subset of
& i% n; l6 d# X' L: P! }! Q ∽ similar to3 w- P- P: s0 r. z( Z3 X
≌ congruent to
) W1 s6 a7 ~5 k7 n/ c8 F p3 V * denotes an operation0 N( @! T. Q5 g8 \/ Y- w) a! j
∴ therefore: i6 t9 H+ |0 C6 a& g
∵ because
]: c0 j. S+ n% Z& s ]; ~ ∶ ratio sign, divided by |