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[GRE数学] 新GRE数学要点:AP

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发表于 2012-8-15 12:55:17 | 显示全部楼层 |阅读模式
AP   Average of n numbers of arithmetic progression (AP) is the average of the smallest and the largest number of them. The average of m number can also be written as x + d(m-1)/2.
3 Z. z+ I8 F& s  Example:; O- b% f" N, s
  The average of all integers from 1 to 5 is (1+5)/2=3
4 V" c/ A4 i. j% A8 t; m  The average of all odd numbers from 3 to 3135 is (3+3135)/2=1569# u+ d4 W$ e8 A9 `1 N8 f( v
  The average of all multiples of 7 from 14 to 126 is (14+126)/2=70. k3 O0 z; w4 M8 s3 F, y
  remember:
7 F+ Q- t3 H! |% V, h9 J  Make sure no number is missing in the middle.' {, X( B  [8 R7 ]
  With more numbers, average of an ascending AP increases.
' Z0 K( \; J# c2 q4 u" V  With more numbers, average of a descending AP decreases.1 K  ?2 P  q( Y  v
  AP:numbers from sum
' f7 j: f, @: @9 @; s+ K( f# H  given the sum s of m numbers of an AP with constant increment d, the numbers in the set can be calculated as follows:4 k* E- L9 F! Y+ K2 b  {
  the first number x = s/m - d(m-1)/2,and the n-th number is s/m + d(2n-m-1)/2.1 R& Q0 Z2 r' b( q
  Example:
' o# j& ^# c: b. i7 L" ]  if the sum of 7 consecutive even numbers is 70, then the first number x = 70/7 - 2(7-1)/2 = 10 - 6 = 4.2 N" V3 D# I9 L' s3 U  K
  the last number (n=m=7)is 70/7+2(2*7-7-1)/2=10+6=16.the set is the even numbers from 4 to 16.
( v2 N* s! m6 H3 B  U0 X  Remember:# e, ?) S, Q) A7 L. H
  given the first number x, it is easy to calculate other numbers using the formula for n-th number: x+(n-1)
; x% [6 F3 b) W+ B, ?9 {5 w  AP:numbers from average' L0 N( s2 n6 N4 A9 {
  all m numbers of an AP can be calculated from the average. the first number x = c-d(m-1)/2, and the n-th number is c+d(2n-m-1)/2, where c is the average of m numbers.
& u9 e; W* T! b# Z8 Q8 r7 H  Example:
6 B) J- G/ P# P: k1 x+ @! ]  if the average of 15 consecutive integers is 20, then the first number x=20-1*(15-1)/2=20-7=13 and the last number (n=m=15) is 20+1*(2*15-15-1)/2=20+7=27.
, }7 Q2 P% }5 _/ W/ r" |  if the average of 33 consecutive odd numbers is 67, then the first number x=67-2*(33-1)/2=67-32=35 and the last number (n=m=33) is 67+2*(2*33-33-1)/2=67+32=99.
  C' n/ o/ S" [7 y. j  Remember:2 q/ w: Q7 G& ^$ v. S
  sum of the m numbers is c*m,where c is the average.
9 [. K7 u$ [) x" Q# k4 s  由于美国数学基础教育的难度增加导致数学考试越来越难,但新gre数学复习考点都是高中时候学到的知识点,考生不要过于紧张,把基本概念弄明白,再记住一些新版gre数学必备的词汇,那么相信新版gre数学应该没有问题。
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