考点三 名词(词组)作同位语
0 o6 P8 K8 P- y$ Q! {同位语主要由名词词组充当, 对其前面的名词或代词作补充说明, 8 d5 V& N+ z7 Q
I came from Jiangying, a very beautiful and peaceful town.2 r1 m8 T1 I: G
例题:
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# f( W5 {4 y8 v* H8 n+ n9 B* T/ _. @In the nineteenth century, Samuel Gridley Howe founded the Perkins School for the Blind, ----for children in Boston, Massachusetts.( ~& |1 N2 Z1 N [7 ]
(A) that institutes0 E% w6 T0 ?5 o8 X2 n9 K( X
(B) while instituted9 ^6 C( X2 F, O! V( r
(C) was an institution" L' F* ^8 B5 J1 X1 }9 ?
(D) an institute ! s0 ^! z1 F' H7 n" m
答案: (D) + V; q& ]* ?" }& \
解释: 空白前的句子结构完整, 空格后的结构和宾语的很相似, (D)为名词词组, 构成宾语的同位语
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Martha Graham, ----, has run her own dance company for half a century.8 _) V2 ~+ s) j2 P5 I, Y0 X7 Y
(A) is the great modern choreographer. n% u: @1 p5 U# u* ?5 ~3 E
(B) one of the great modern choreographers5 i+ F- ?3 Q6 H
(C) that the great modern choreographers
& i Z4 B: S; A7 | (D) the modern choreographers were great . Z F9 G6 e5 o" x& S& M9 a
答案：B . c) _- U% s( i% }3 v2 B: q
解释：此句主谓俱全, 空格设在主语和谓语之间, 且两端都有逗号, 推知缺少的是主语的同位语, B是名词词组, 可以胜任；A D中的动词与原句谓语冲突; C 不是完整的同位语从句3 Q' {4 j! i8 `: N: {
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考点四 名词(词组)作定语
T( u( K3 t. A( y9 {$ w/ G名词修饰名词作定语的现象在英语中也屡见不鲜, 此时前面的名词相当于形容词的作用, 只是依英语习惯决定究竟用名词还是形容词作定语, TOEFL有少量题涉及这一问题$ V0 m. W- n: G
这样的词语有：word order（词序）， taxi driver（出租车司机）等 4 ^2 a, ~1 x0 K4 n& u1 X
例题:5 M6 R. Z' `! F% D( O7 b/ x
(1) . o9 @: {2 B8 |9 v2 I, o- t
Situated in the heart of a grain-farming and livestock-raising region, Abilene, Kansas, is a prosperous trading and distribute center.
1 n. A$ e8 k1 i* g应改为: distribution/ distributing.
$ R2 O1 k) A4 d g o$ Y解释: 动词distribute不能修饰名词center，可改用名词或分词, 但此题中名词distribution作定语更符合英文习惯
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, [' e4 j& p$ [) ]Acrylic paint enables artists to experiment with many colors effects., ~& f! U5 F5 I9 t3 y. a
应改为: color4 B; F) I. g0 y. ]6 ?1 P
解释: 此处名词color作effects的定语无需用复数, 意为色彩效果 |
发表于 2012-8-14 23:32:39
